http://embeddedgurus.com/stack-overflow/2008/11/modulo-means/ Thoughts on embedded systems by Nigel Jones Sun, 06 May 2012 10:34:02 +0000 hourly 1 http://wordpress.org/?v=3.3.1 http://embeddedgurus.com/stack-overflow/2008/11/modulo-means/comment-page-1/#comment-63 Bruno Santiago Tue, 25 Nov 2008 23:00:00 +0000 http://www.gfcdev.org/test-stack/2008/11/21/modulo-means/#comment-63 If you want to average a small power of two samples it can be efficient.This way, you can average two by two and it´s a lot easier.Imagine you have sample A and sample B.If | A - B | <= 8 (or 180 degrees), then it´s plain ( A + B ) / 2If | A - B | > 8 and A + B >= 16 (or 360 degrees), then it's ( A + B - 16 ) / 2If | A - B | > 8 and A + B < 16, then it's 16 + [ ( A + B - 16 ) / 2 ] If you want to average a small power of two samples it can be efficient.This way, you can average two by two and it´s a lot easier.Imagine you have sample A and sample B.If | A – B | <= 8 (or 180 degrees), then it´s plain ( A + B ) / 2If | A – B | > 8 and A + B >= 16 (or 360 degrees), then it's ( A + B – 16 ) / 2If | A – B | > 8 and A + B < 16, then it's 16 + [ ( A + B - 16 ) / 2 ]

]]> http://embeddedgurus.com/stack-overflow/2008/11/modulo-means/comment-page-1/#comment-62 Bruno Santiago Tue, 25 Nov 2008 15:36:00 +0000 http://www.gfcdev.org/test-stack/2008/11/21/modulo-means/#comment-62 Victorh:The point is he is measuring phase. If the phase difference is greater than 359 degrees, it is 0 again.Nigel:Why not average the inputs of the phase comparator?If it´s not possible, you can think you´re working with polar cordinates and measuring only the angle. Choose an arbritary radius and then convert to cartesian cordinates. Then average x and y. Then convert back to polar coordinates and take angle.Thus, it´s probably not efficient at all. Victorh:The point is he is measuring phase. If the phase difference is greater than 359 degrees, it is 0 again.Nigel:Why not average the inputs of the phase comparator?If it´s not possible, you can think you´re working with polar cordinates and measuring only the angle. Choose an arbritary radius and then convert to cartesian cordinates. Then average x and y. Then convert back to polar coordinates and take angle.Thus, it´s probably not efficient at all.

]]> http://embeddedgurus.com/stack-overflow/2008/11/modulo-means/comment-page-1/#comment-61 victorh Mon, 24 Nov 2008 16:21:00 +0000 http://www.gfcdev.org/test-stack/2008/11/21/modulo-means/#comment-61 To be honest, I completely missed your point. I can't even understand what your problem is. I got loss in:<i>Indeed we can do this <b>here</b>, provided that we don't flip back and fore across the zero line.</i>"here" where?In the past, I have enjoyed your posts. I even applied on my projects some of the knowledge you put in them. So I believe this post also includes some clever insight which, unfortunately, I missed to understand.Maybe you could rephrase it? Thanks :) To be honest, I completely missed your point. I can’t even understand what your problem is. I got loss in:Indeed we can do this here, provided that we don’t flip back and fore across the zero line.“here” where?In the past, I have enjoyed your posts. I even applied on my projects some of the knowledge you put in them. So I believe this post also includes some clever insight which, unfortunately, I missed to understand.Maybe you could rephrase it? Thanks

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